import XCTest
@testable import ARDemo

//创建CalculatorTests类，继承自XCTestCase
class CalculatorTests: XCTestCase {

    var calculator: Calculator!

    //测试开始前，初始化要使用的环境变量
    override func setUp() {
        super.setUp()
        calculator = Calculator()
    }

    //测试结束后，清理使用的环境变量
    override func tearDown() {
        super.tearDown()
        calculator = nil
    }

    //要控制测试用例的执行顺序
    //1.可以通过test+101这种形式，顺序会根据test后面的数字，先小，后大的顺序进行执行
    func test101Addition() {
        let result = calculator.add(2, 3)
        XCTAssertEqual(result, 5, "Addition of 2 and 3 should be 5")
    }

    func test102Addition() {
        let result = calculator.add(2, 3)
        XCTAssertEqual(result, 5, "Addition of 2 and 3 should be 5")
    }

    func test103Addition() {
        let result = calculator.add(2, 3)
        XCTAssertEqual(result, 5, "Addition of 2 and 3 should be 5")
    }

    //2.使用测试用例组的形式，执行顺序会按照组中的顺序，由上到下进行执行
    func testAddition() {
        let result = calculator.add(2, 3)
        XCTAssertEqual(result, 5, "Addition result is incorrect")
    }

    func testSubtraction() {
        let result = calculator.subtract(5, 2)
        XCTAssertEqual(result, 3, "Subtraction result is incorrect")
    }
    //静态变量allTests中放置排序后的测试用例
    static var allTests = [
        testCase(CalculatorTests.testAddition),
        testCase(CalculatorTests.testSubtraction)
    ]

    //测试异步方法
    func testAsyncHTTPRequest() {
        let expectation = XCTestExpectation(description: "HTTP request")
        
        // 调用异步HTTP请求方法
        asyncHTTPRequest { response in
            // 处理回调结果
            XCTAssertTrue(response.success)
            expectation.fulfill()
        }
        
        // 等待异步操作完成
        wait(for: [expectation], timeout: 5.0)
    }

    //测试功能的执行性能
    func testPerformance() {
        measure([.wallClockTime, .userTime]) {
            // 执行需要测试性能的代码块
        }
    }

}


class Calculator {
    func add(_ a: Int, _ b: Int) -> Int {
        return a + b
    }

    func subtract(_ a: Int, _ b: Int) -> Int {
        return a - b
    }
}